The graph below shows the "x-direction" position of a charged particle flying around in space and accelerating due only to some electric field. During which time interval is the force on the particle in the x-direction greatest?
A
5 to 6 seconds
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
6 to 7 seconds
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
7 to 8 seconds
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
8 to 9 seconds
No worries! We‘ve got your back. Try BYJU‘S free classes today!
E
10 to 11 seconds
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is B6 to 7 seconds The force acting a particle is given by F=ma=mdvdt=md2xdt2.
Hence the direction of force is the sign of the rate of change of slope of the curve.
For options A, C, D and E, the slope of the curves is constant.
For option B, from 6 to 7 seconds, the slope of curve is going from being negative to positive. Hence it is increasing positively, and hence the particle is accelerating.