Question

The graph between displacement $\left(\text{x}\right)$ from mean position and time $\left(\text{t}\right)$ for a particle undergoing SHM is as shown in the figure.


The corresponding acceleration-time $\left(\text{a-t}\right)$ graph is

• A.
• B.
• C.
• D.

Answer 1

The correct option is C

For SHM, acceleration is related to displacement as

$a=-{\omega }^{2}x$

as $x=A\sin \left(\omega t\right)$

$v=\frac{dx}{dt}=\omega A\cos \left(\omega t\right)$

$a=\frac{dv}{dt}=-{\omega }^{2}A\sin \left(\omega t\right)$