The graph between displacement $(x)$ from mean position and time $(t)$ for a particle undergoing SHM is as shown in the figure.

The corresponding acceleration-time $(a-t)$ graph is

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Solution

The correct option is C
For SHM, acceleration is related to displacement as

$a = - ω^{2} x$

as $x = A sin (ω t)$

$v = \frac{d x}{d t} = ω A cos (ω t)$

$a = \frac{d v}{d t} = - ω^{2} A sin (ω t)$

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The graph between displacement (x) from mean position and time (t) for a particle undergoing SHM is as shown in the figure. The corresponding acceleration-time (a-t) graph is

The correct option is C For SHM, acceleration is related to displacement as a=−ω2x as x=Asin(ωt) v=dxdt=ωAcos(ωt) a=dvdt=−ω2Asin(ωt)

The graph between displacement $(x)$ from mean position and time $(t)$ for a particle undergoing SHM is as shown in the figure.

The corresponding acceleration-time $(a-t)$ graph is

The correct option is C
For SHM, acceleration is related to displacement as

$a = - ω^{2} x$

as $x = A sin (ω t)$

$v = \frac{d x}{d t} = ω A cos (ω t)$

$a = \frac{d v}{d t} = - ω^{2} A sin (ω t)$