The graph between logRR0 and log A is R-radius of nucleus- A- mass number

The expression for the radius of the nucleus is given by, R=R_0A^13 ⇒ nbsp; log( RR_0) = log (A^13) ⇒ nbsp; log(RRo) nbsp; = 13log A The above equatio ...

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Standard XII

Physics

Validating the Bohr's Model

The graph bet...

Question

The graph between $log (\frac{R}{R_{0}}) and log A$ is

$(R - radius of nucleus; A - mass number)$

Straight line

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Solution

The correct option is A Straight line
The expression for the radius of the nucleus is given by,

$R = R_{0} A^{\frac{1}{3}}$

$\Rightarrow log (\frac{R}{R_{0}}) = log (A^{\frac{1}{3}})$

$\Rightarrow log (\frac{R}{R o}) = \frac{1}{3} log A$

The above equation is of the form of $y = m x$ , which represents the straight line.

Hence, option $(A)$ is correct.

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The graph between log(RR0) and logA is (R−radius of nucleus; A−mass number)

The correct option is A Straight lineThe expression for the radius of the nucleus is given by, R=R0A13 ⇒log(RR0)=log(A13) ⇒log(RRo)=13logA The above equation is of the form of y=mx, which represents the straight line. Hence, option (A) is correct.

The graph between $log (\frac{R}{R_{0}}) and log A$ is

$(R - radius of nucleus; A - mass number)$