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Question

The graph between logT50 and log(1a) (where T50 and a are the half - life period and the concentration respectively) for a nth order reaction is of the type:

What is the value of n?

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Solution

Rate=k[A]n
Half-life of nth order by solving the integrated form of the above equation
A1n021n×(1n)A1n0(1n)=kt
(n1)log1A0+log(1(2)1n(1n)11n)=logk+logt50
slope is n1 which is equal to tan 450
n1=1
n=2

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