The graph between magnitude of electric field intensity due to a positive point charge, as a function of inverse of distance from it is

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Ellipse

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Hyperbola

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Parabola

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Straight Line

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Solution

The correct option is C Parabola
The electric field intensity due to a point charge at a distance r from it is $E = \frac{K Q}{r^{2}}$
$\Rightarrow E = K Q {(\frac{1}{r})}^{2}$
$\Rightarrow E \propto {(\frac{1}{r})}^{2}$ $\Rightarrow E \propto x^{2} (where x = \frac{1}{r})$
$\Rightarrow$ Graph is a parabola.

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The graph between magnitude of electric field intensity due to a positive point charge, as a function of inverse of distance from it is [0.77 Mark]

The correct option is C ParabolaThe electric field intensity due to a point charge at a distance r from it is E=KQr2 ⇒E=KQ(1r)2 ⇒E∝(1r)2 ⇒E∝x2(where x=1r) ⇒ Graph is a parabola.

The graph between magnitude of electric field intensity due to a positive point charge, as a function of inverse of distance from it is

$[$ 0.77 Mark $]$