The graph between the resistive force $F$ acting on a body and the distance covered by the body is shown in the figure. The mass of the body is $25$ kg and the initial velocity is $2$ m/s. When the distance covered by the body is $4$ , its kinetic energy would be:

50

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20

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Solution

The correct option is A $50$ J
kinetic energy

$k = \frac{1}{2} m v^{2}$

m is mass
v is velocity

$K = \frac{1}{2} m V^{2} = \frac{1}{2} \times 25 \times 2^{2} = \frac{1}{2} \times 25 \times 4$

$K = 50 = 50 J$

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The graph between the resistive force F acting on a body and the distance covered by the body is shown in the figure. The mass of the body is 25 kg and the initial velocity is 2m/s. When the distance covered by the body is 4, its kinetic energy would be:

The correct option is A 50 Jkinetic energy k=12mv2m is massv is velocityK=12mV2=12×25×22=12×25×4 K=50=50J

The graph between the resistive force $F$ acting on a body and the distance covered by the body is shown in the figure. The mass of the body is $25$ kg and the initial velocity is $2$ m/s. When the distance covered by the body is $4$ , its kinetic energy would be:

The correct option is A $50$ J
kinetic energy

$k = \frac{1}{2} m v^{2}$

m is mass
v is velocity

$K = \frac{1}{2} m V^{2} = \frac{1}{2} \times 25 \times 2^{2} = \frac{1}{2} \times 25 \times 4$

$K = 50 = 50 J$