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Boyle's Law

The graph dra...

Question

The graph drawn between presure and volume in boyles law experiment is shown in figure, then:

T_{1} > T_{2}

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T_{2} > T_{1}

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T_{1} = T_{2}

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\frac{T_{1}}{T_{2}} = C

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Solution

The correct option is B $T_{2} > T_{1}$
From ideal gas equation, PV = nRT
consider a particular volume $V_{0}$
at this volume, clearly from the graph, the PV curve at temperature $T_{2}$ has more pressure that the pressure of PV curve at temperature $T_{1}$
So, $T_{2} > T_{1}$

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