The graph drawn with object distance along abscissa and image distance along ordinate measuring the distance from the convex lens is :
In a convex lens, 1v−1u=1f
Or 1v−1f=1u where u is always negative and f is always positive.
1v=1f−1u
So, as u is increased 1/u will decrease and 1f−1u will increase, so, 1v increases or v decreases.
So, its graph will be a hyperbola