The graph for the logarithmic functiony-logmx- - m-1 is

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Question

The graph for the logarithmic function
$y = l o g_{m} x, \forall m > 1$ is

True

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False

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If log (m+n)=log m+ log n ,show that n=m/(m-1).

f

f (x) = ln (x - 1) + 1

{log}_{m + 1} (x + \sqrt{m + 1} y) + {log}_{m + 1} (x - \sqrt{m + 1} y) = 1

m > 0

log (m + n) = log m + log n

n

m

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