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Question

The graph of a quadratic polynomial f(x)=ax2+bx+c is shown below. Then which of the following option(s) is/are correct ?


A
c<0
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B
b>0
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C
a+bc>0
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D
abc<0
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Solution

The correct option is D abc<0

Since, graph is upward opening.
a>0
Graph intersects with yaxis in ve region.
c<0
Now, the vertex of the parabola is in ve side of the xaxis.
b2a<0b>0

abc<0
a+b>0, c<0a+b>0, c>0a+bc>0

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