The graph of a quadratic polynomial f(x)=ax2+bx+c is shown below. Then which of the following option(s) is/are correct ?
A
c<0
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B
b>0
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C
a+b−c>0
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D
abc<0
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Solution
The correct option is Dabc<0
Since, graph is upward opening. ∴a>0
Graph intersects with y−axis in −ve region. ∴c<0
Now, the vertex of the parabola is in −ve side of the x−axis. ∴−b2a<0⇒b>0