Question

The graph of $f\left(x\right)=2x^2-3x+2$ is

• A.
  
• B.
  
• C.
  
• D.
  

Answer 1

The correct option is A


$f\left(x\right)=2x^2-3x+2$
$a>0$
Graph of parabola is upward opening.
$D=9-4\times 2\times 2=-7<0$
It does not touch $x-$ axis.
$-\frac{b}{2a}=\frac{3}{4}-\frac{D}{4a}=\frac{7}{8}$
The vertex $(\frac{3}{4},\frac{7}{8})$ of the parabola lies in the first quadrant.
$f\left(0\right)=2$
$y-$ intercept is $2$.
Therefore, the graph which follow all the above conditions is