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Question

The graph of f(x)=ax2+bx+c is shown below, such that b24ac=4. If the length of segment AB and AC are 1 and 4 respectively, then the value of (a+b+c) is equal to



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Solution

f(x)=ax2+bx+c
D=b24ac=4 ...(1)
Least value of f(x)=D4a=¯¯¯¯¯¯¯¯AB
D4a=1
(4)=4a [From (1)]
a=1

Also b2a=4b=8
And b24ac=4
644c=4
c=17
Hence, a+b+c=1+8+17=26

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