Question

The graph of the equation $x^2+y^2=169$ is a circle. Which of the following points is outside the circle?

• A. (5, 12)
• B. (9, 9)
• C. (11, 5)
• D. (10, 10)
• E. none of these

Answer 1

Answer: (D)

(10, 10)

• The center of given circle is $(0,0)$ and the radius is $\sqrt{169}=13$
• For the point to lie on outside the circle , the distance of that point from center must be greater than radius
• Consider point $(10,10)$ , the distance of it from center is $10\sqrt{2}>13$
• Therefore the correct option is $D$