The graph of the equation $y = 2 x + 3$ lies in quadrants

I and II only

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I and III only

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II and III only

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I, II, and III only

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II, III, and IV only

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Solution

The correct option is D I, II, and III only
Given:
$y = 2 x + 3$

if $y = 0$ then $0 = 2 x + 3$

$\Rightarrow x = \frac{- 3}{2}$

$\Rightarrow A \equiv (\frac{- 3}{2}, 0)$

if $x = 0$ then $y = 2 \times 0 + 3$

$\Rightarrow y = 3$

$\Rightarrow B \equiv (0, 3)$

so, clearly we can see the line is in I, II, III quadrants.

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