Question

The graph of the line $5x+3y=4$ cuts the $y$-axis at the point

• A. $(0,\frac{4}{3})$
• B. $(0,\frac{3}{4})$
• C. $(\frac{4}{5},0)$
• D. $(\frac{5}{4},0)$

Answer 1

The correct option is A $(0,\frac{4}{3})$

Given equation is :
$5x+3y=4$
Convert this equation in slope intercept form:
$\Rightarrow -3y=5x+(-4)$
$\Rightarrow y=d\frac{5x}{-3}+\frac{(-4)}{-3}$
$\Rightarrow y=-\frac{5}{3}x+\frac{4}{3}$
Now comparing above equation with slope intercept form $y=mx+b$
We get $y$-intercept $b$ as $\frac{4}{3}$
Hence, this equation will cut $y$-axis at $(0,\frac{4}{3})$