Question

Question 5
The graph of the linear equation 2x + 3y = 6 cuts the y-axis at the point:


A) (2, 0)
B) (0, 3)
C) (3, 0)
D) (0, 2)

Answer 1

The answer is D.
Since, the graph of linear equation 2x + 3y = 6 cuts the y-axis,
Put x = 0 in the given equation 2x + 3y = 6 we get
$2\times 0+3y=6$
$\Rightarrow$ $3y=6$
$\Rightarrow y=\frac{6}{3}$
$\therefore$ $y=2$
Hence, at the point (0, 2) the given linear equation cuts the y-axis.