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Question

The graph of the linear equation 4x + 3y = 12 cuts the y-axis at the point
(a) (4, 0)
(b) (0, 4)
(c) (0, 3)
(d) (3, 0)

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Solution

(d) (3, 0)
Given equation: 4x + 3y = 12

Or, x =12-3y4

When, y = 0, x = 12-04 = 3
Thus, the graph cuts the x-axis at (3,0).

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