The graph of the linear equation 5x + 3y = 10 is a line that meets the x-axis at the point:

(0, 3)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

(3, 0)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

(2, 0)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

(0, 2)

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D (0, 2)

Taking option D

Substituting co-ordinates of the point (a,−a) in the equation x+y=0

We get a + (−a) = a − a = 0

LHS = RHS

Hence, (a,−a) satisfies x+y=0.

Hence, option D is correct.

Suggest Corrections

Similar questions

Q. The graph of the linear equation 2x + 5y = 10 is the line which meets the y-axis at the point
(a) (0, 2)
(b) (5, 0)
(c)

(\frac{1}{2}, 2)

(d) (2, 1.2)

Q. The graph of the equation

5 x - 3 y = 10

cuts the

x

-axis at the point

A line 5x + 3y + 15 = 0 meets y - axis at point P. Find the co-ordinates of point P. Find the equation of a line through P and perpendicular to x - 3y + 4 = 0.

Q. The graph of the linear equation 3x + 2y = 6 is the line which meets the x-axis at the point
(a) (0, 3)
(b) (2, 0)
(c) (2, 3)
(d) (3, 2)

The graph of the linear equation: 2x + 3y = 6, cuts the x-axis at the point _______.

Join BYJU'S Learning Program

The graph of the linear equation 5x + 3y = 10 is a line that meets the x-axis at the point:

The correct option is D (0, 2) Taking option D Substituting co-ordinates of the point (a,−a) in the equation x+y=0 We get a + (−a) = a − a = 0 LHS = RHS Hence, (a,−a) satisfies x+y=0. Hence, option D is correct.

The correct option is D (0, 2)

Taking option D

Substituting co-ordinates of the point (a,−a) in the equation x+y=0

We get a + (−a) = a − a = 0

LHS = RHS

Hence, (a,−a) satisfies x+y=0.

Hence, option D is correct.