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Question

The graph of the quadratic polynomial ; y=ax2+bx+c is as shown in the figure. Then
298094_416b67f52ac44fdab468872cf05ee121.png

A
b24ac>0
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B
b>0
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C
a<0
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D
All of these
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Solution

The correct option is D All of these
Clearly we see that the quadratic equation has 2 real roots
b24ac>0
And vertex of parabola lies in fourth quadrant x is positive and y is negative
Coordinates of vertex of parabola =(b2a,4acb24a)
As y is negative 4acb24a<0
a>0 as 4acb24a<0
And x coordinate is positive b2a>0
b<0
Final answer is: b24ac>0,b<0,a>0

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