The correct option is B Given : |x|+|y| nbsp; =1 |y|=1 |x| ⇒ y = ± (1 |x|) We know y=|x| So y = |x| For y=1 |x|, shifting y= |x| upwards by 1 unit. No ...

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Standard XII

Mathematics

Graph of sgn(x)

+̂

Question

The graph of $| x | + | y | = 1$ is

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Solution

The correct option is B
Given : $| x | + | y | = 1$
$| y | = 1 - | x | \Rightarrow y = \pm (1 - | x |)$
We know $y = | x |$

So $y = - | x |$

For $y = 1 - | x |$ , shifting $y = - | x |$ upwards by $1$ unit.

Now, taking mirror image about $x -$ axis, we get
$y = - (1 - | x |)$
Hence, the graph of $| x | + | y | = 1$ is

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The graph of |x|+|y|=1 is

The correct option is B Given : |x|+|y|=1 |y|=1−|x|⇒y=±(1−|x|) We know y=|x| So y=−|x| For y=1−|x|, shifting y=−|x| upwards by 1 unit. Now, taking mirror image about x− axis, we get y=−(1−|x|) Hence, the graph of |x|+|y|=1 is

The graph of $| x | + | y | = 1$ is