Question

The graph of $|x|+|y|=1$ is

• A.
• B.
• C.
• D.

Answer 1

The correct option is B

Given : $|x|+|y|=1$
$|y|=1-|x|\Rightarrow y=\pm (1-|x|)$
We know $y=|x|$


So $y=-|x|$


For $y=1-|x|$, shifting $y=-|x|$ upwards by $1$ unit.


Now, taking mirror image about $x-$ axis, we get
$y=-(1-|x|)$
Hence, the graph of $|x|+|y|=1$ is