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Question

The graph of |x|+|y|=1 is

A
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B
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Solution

The correct option is B
Given : |x|+|y|=1
|y|=1|x|y=±(1|x|)
We know y=|x|


So y=|x|


For y=1|x|, shifting y=|x| upwards by 1 unit.


Now, taking mirror image about x axis, we get
y=(1|x|)
Hence, the graph of |x|+|y|=1 is


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