The graph represented by the equation $x = {sin}^{2} t, y = 2 cos t$ is

a portion of a parabola

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a parabola

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a part of sine graph

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a part of hyperbola

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Solution

The correct option is B a portion of a parabola
$x = 1 - {cos}^{2} t$
$x = 1 - \frac{y^{2}}{4}$
$y^{2} = 4 (1 - x)$
This equation represents a parabola where
$0 < x < 1$ and $- 2 < y < 2$

Suggest Corrections

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