The graph represents the s-t curve of a body moving in a straight line. At which moment 't' is the instantaneous velocity approximately equal to the average velocity over the first 't' seconds?

$t = t_{1}$

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$t = t_{2}$

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$t = t_{3}$

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$t = t_{4}$

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Solution

The correct option is C
$t = t_{3}$

From the hint, we can see that, we need to find a point 't' such that slope of the tangent at the point equals the slope of the line joining the origin and the point.

Therefore closest answer is $t_{3}$ .

Extra:-

Average Velocity = $\frac{d i s p l a c e m e n t}{t i m e t a k e n}$ = $\frac{△ g}{△ x}$

From the figure we can see that average velocity is equal to slope of OA.

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