The graph shown in the figure represent change in the temperature of $5 k g$ of a substance as it absorbs heat at a constant rate of $42 k J / m i n$ . The latent heat of vaporization of the substance is

630 k J k g^{- 1}

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126 k J k g^{- 1}

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84 k J k g^{- 1}

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12.6 k J k g^{- 1}

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Solution

The correct option is D $84 k J k g^{- 1}$
First mass will melt and then vaporize ,we can see there is a constant temperature line at $T = 125^{o} C$ , that is its vaporization temperature , and heat supplied during that duration is latent heat of vaporization.
Heat absorbed is $42 \times (35 - 25) = 5 \times L$
so, $L = 84 k J / k g$

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The graph shown in the figure represent change in the temperature of 5 kg of a substance as it absorbs heat at a constant rate of 42 kJ/min. The latent heat of vaporization of the substance is

The correct option is D 84kJkg−1First mass will melt and then vaporize ,we can see there is a constant temperature line at T=125oC , that is its vaporization temperature , and heat supplied during that duration is latent heat of vaporization. Heat absorbed is 42×(35−25)=5×Lso, L=84 kJ/kg

The graph shown in the figure represent change in the temperature of $5 k g$ of a substance as it absorbs heat at a constant rate of $42 k J / m i n$ . The latent heat of vaporization of the substance is