Question

The graphs of $2x+3y-6=0$, $4x-3y-6=0$, $x=2$ and $y=\frac{2}{3}$ intersect in

• A. four points
• B. one point
• C. in no points
• D. infinite number of points

Answer 1

The correct option is B one point

Given

$2x+3y-6=0$------(1)

$4x-3y-6=0$------(2)

$x=2$------(3)

$y=\frac{2}{3}$------(4)

on solving eq (1) and (2) we get

$x=2,y=\frac{2}{3}$

Hence point if intersection is P$(2,\frac{2}{3})$

Also $x=2$ & $y=\frac{2}{3}$ passes through the Point p.

Hence all passes through only one Point P