Question

The graphs of $2x+3y-6=0$ and $4x-3y-6=0$, $x=2$ and $y=\frac{2}{3}$ intersects in

• A. Four points
• B. one point
• C. two point
• D. infinite no. of points

Answer 1

Answer: (B)

one point

Intersection point of
$2x+3y-6=0$ and $4x-3y-6=0$
$2x+3y-6=0$
$4x-3y-6=0$
-------------------
$6x-12=0$
$x=2$
Substitute $x=2$ in $2x+3y-6=0$
$2\left(2\right)+3y-6=0$
$4+3y-6=0$
$y=2/3$
So, $2x+3y-6=0$, $4x-3y-6=0$
$x=2$ and $y=2/3$ intersects in one point.