Question

The graphs of $y={\cosh }^{-1}\left(x\right)$ is the mirror image of that of $y=\cosh \left(x\right)$ along the line y=x for all $x<0$.

• A. True
• B. False

Answer 1

The correct option is B False

$\because$ for all $x<0$, ${\cosh }^{-1}x$ is not defined. So the graph is not possible hence its not possible to extract graph as mirror image of $\cosh x$