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Question

The graphs of y=sinh−1(x) is the mirror image of that of y=sinh(x) along which of the following lines?

A
y=0
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B
x=0
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C
y=x
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D
y=x
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Solution

The correct option is D y=x
y=sinhx and y=sinh1x can be drawn as shown in the figure. It is clearly seen that the mirror image of y=x
1174194_989161_ans_d70009a9d8434ae1a37eda69b86acecd.PNG

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