The correct option is
A The radius of the first Bohr orbit is much greater than the estimated size of the whole universe.
Radius of the first Bohr orbit is given by the relation,
r1=4πϵ0(h2π)2mee2 ......(1)
Where,
ϵ0= Permittivity of free space
h= Planck's constant
me= Mass of an electron
e= Charge of an electron
mp= Mass of a proton
r= Distance between the electron and the proton
Coulomb attraction between an electron and a proton is given as:
FC=e24πϵ0r2 .....(2)
Gravitational force of attraction between an electron and a proton is given as:
FG=Gmpmcr2 .....(3)
Where
G= Gravitation constant =6.67×10−11Nm2/kg2
If an electrostatic (Coulomb) force and the gravitation force between an electron and a proton are equal, then we can write:
FG=FC
Gmpmcr2=e24πϵ0r2
∴e24πϵ0=Gmpmc .....(4)
Putting the value of equation ( 4 ) in equation ( 1 ), we get:
r1=(h2π)2Gmpm2c
=(6.63×10−342×3.14)26.67×10−11×1.67×10−27×(9.1×10−31)2≈1.21×1029m
It is known that the universe is 156 billion light years wide or 1.5×1027m wide. Hence, we can conclude that the radius of the first Bohr orbit is much greater than the estimated size of the whole universe.