The gravitational field due to a mass distribution is given by E=−K/x3 in x−direction. Taking the gravitational potential to be zero at infinity, find its value at a distance x.
A
−3K2x2
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B
−K3x2
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C
−2K3x2
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D
K2x2
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Solution
The correct option is DK2x2 The change in potential in going from the initial to find position in a gravitational field E is given by
∫fidV=−∫fi→E⋅→dr
Since the change in field is only in the x− direction