1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

# The gravitational field in a region is given by −→Eg=(4^i+^j) N/kg. Work done by this field will be zero when the particle is moved along the line

A
y+4x=2
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
4y+x=6
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
x+y=5
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
xy=5
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

## The correct option is A y+4x=2Given that, Gravitational field, −→Eg=(4^i+^j) N/kg The gravitational force (→F) on the particle will be extended along the direction of gravitational field. Thus, workdone (W) by gravitational field will be zero if →E is perpendicular to the direction of displacement (→S). As, W=→F.→S So, W=0, if →F⊥→S or −→Eg⊥→S The slope of gravitational field line is tanθ=m1=14 ⇒tanθ=m1=14 Let, the slope of the direction of displacement of the particle is m2. The displacement of the particle will be perpendicular to field line only when, m1m2=−1..(1) Substitute m1 in equation (1), we get m2=−4 From the equation of the straight line given in option (a), y+4x=2 ⇒y=−4x+2 It's slope =−4 So, this is the correct equation of straight line. Why this question ? To make the student familiar with the application of straight line equation in the concept of gravitation. Such type of problems are useful to enhance the thinking capacity of students.

Suggest Corrections
8
Join BYJU'S Learning Program
Join BYJU'S Learning Program