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EMF and EMF Devices

The gravitati...

Question

The gravitational field in a region is given by $\to E = 5 N / k g^i + 12 N / k g^j$ . The change in the gravitational potential energy of a particle of mass $2 k g$ when it is taken from the origin to a point $(7 m, - 3 m)$ is :

71 J

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13 \sqrt{58} J

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- 71 J

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- 2 J

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Solution

The correct option is D $- 2 J$
The potential at a given point as , V = $\int E d x$
Thus, $V = (5 i + 12 j) . (7 i - 3 j)$
$V = 35 - 36 = - 1$
Thus, the change in potential energy is $m V$ $= - 2 J$

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Similar questions

\to E = 5 N / k g^i + 12 N / k g^j

1 k g

\to E = (5 N {k g}^{- 1}) \to i + (12 N {k g}^{- 1}) \to j

2 k g

(12 m, 5 m)

¯ E = (5 N / k g)^i + (12 N / k g)^j

(12 m, 0)

(0, 5 m)

\to E = (5^i + 12^j) N / k g

2 k g

(12 m, 5 m)

\to E = (5 N k g^{- 1}) \to i + (12 N k g^{- 1}) \to j

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