MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Free Fall

The gravitati...

Question

The gravitational force between two stones of mass 1 kg each separated by a distance of 1 metre in vacuum is

A

Zero

No worries! We‘ve got your back. Try BYJU‘S free classes today!

B

No worries! We‘ve got your back. Try BYJU‘S free classes today!

C

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

D

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C

$F = G \frac{m_{1} m_{2}}{r^{2}} = 6.675 \times \frac{1 \times 1}{1^{2}} \times 10^{- 11} = 6.675 \times 10^{- 11} N$

Suggest Corrections

thumbs-up

24

Similar questions

Q. The gravitational force between two stones of mass

1 k g

each, separated by a distance of

1 m

in a vacuum is (

G = 6.674 \times 10^{- 11} N m^{2} / k g^{2}

)

Q. The force of gravitation between two bodies of mass 1 kg each separated by a distance of 1 m in vaccum is

Q. Determine the gravitational force of two particle of mass

3 k g

7 k g

separated by a distance

2 m

.

Q. The force ofgravitation between two bodies of mass 1kg each separated by a distance of 1 m in vacuum is:

Q. Two spherical balls of mass 1 kg and 4 kg are separated by a distance of 12 cm. The distance from 1 kg at which the gravitational force on any mass becomes zero.

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Free Fall Tackle

PHYSICS

Watch in App

explore_more_icon

Explore more

Standard X Physics

Join BYJU'S Learning Program

CrossIcon