The gravitational force between two stones of mass 1 kg each, separated by a distance of 1 m in vacuum is.

zero

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6.675 \times 10^{- 6} N

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8.326 \times 10^{- 8} N

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6.675 \times 10^{- 11} N

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Solution

The correct option is D $6.675 \times 10^{- 11} N$
force due to gravity is given by $F = \frac{G m_{1} m_{2}}{r^{2}}$
where G is gravitational constant $G = 6.675 \times 10^{- 11}$
also $m_{1} = m_{2} = 1 k g$ , $r = 1 m$
so $F = \frac{G 1.1}{1^{2}} =$ $G = 6.675 \times 10^{- 11} N .$
so correct option is option D.

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The gravitational force between two stones of mass 1 kg each, separated by a distance of 1 m in vacuum is.

The correct option is D 6.675×10−11Nforce due to gravity is given by F=Gm1m2r2where G is gravitational constant G=6.675×10−11also m1=m2=1kg, r=1mso F=G1.112=G=6.675×10−11N.so correct option is option D.