The gravitational force of attraction between two masses depend on the distance between them is $G =$ gravitaional constant $= k \times 10^{- 11} N m^{2} k g^{- 2}$ . what is the value of k?

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Solution

Newton's Law of Gravitation says,
$F_{g} = G \frac{m_{1} \times m_{2}}{r^{2}}$
where F $= G r a v i t a t i o n a l F o r c e$
$m_{1}, m_{2} =$ masses of two bodies
$r =$ distance
$G =$ gravitaional constant $= 6.673 \times 10^{- 11} N m^{2} k g^{- 2}$
Hence, $K = 6.673$

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The gravitational force of attraction between two masses depend on the distance between them is G=gravitaional constant =k×10−11Nm2kg−2. what is the value of k?

Newton's Law of Gravitation says, Fg=Gm1×m2r2where F=Gravitational Forcem1,m2= masses of two bodiesr= distanceG=gravitaional constant =6.673×10−11Nm2kg−2Hence, K=6.673

The gravitational force of attraction between two masses depend on the distance between them is $G =$ gravitaional constant $= k \times 10^{- 11} N m^{2} k g^{- 2}$ . what is the value of k?

Newton's Law of Gravitation says,
$F_{g} = G \frac{m_{1} \times m_{2}}{r^{2}}$
where F $= G r a v i t a t i o n a l F o r c e$
$m_{1}, m_{2} =$ masses of two bodies
$r =$ distance
$G =$ gravitaional constant $= 6.673 \times 10^{- 11} N m^{2} k g^{- 2}$
Hence, $K = 6.673$