The gravitational potential in a region is given by V = (3x + 4y + 12z) $\frac{J}{k g}$ . The modulus of the gravitational field at (x = 1, y = 0, z = 3) is

$20 N k g^{- 1}$

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$13 N k g^{- 1}$

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$12 N k g^{- 1}$

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$5 N k g^{- 1}$

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Solution

The correct option is B
$13 N k g^{- 1}$

$I = - (\frac{δ v}{δ x}^i + \frac{δ v}{δ y}^j + \frac{δ v}{δ z}^k) = - (3^i + 4^j + 12^k) [A s V = (3 x + 4 y + 12 z) (g i v e n)]$

It is uniform field Hence its value is same every where $| I | = \sqrt{3^{2} + 4^{2} + 12^{2}} = 13 N k g^{- 1}$

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The gravitational potential in a region is given by V = (3x + 4y + 12z)Jkg. The modulus of the gravitational field at (x = 1, y = 0, z = 3) is

The correct option is B 13 N kg−1 I=−(δvδx^i+δvδy^j+δvδz^k)=−(3^i+4^j+12^k)[As V=(3x+4y+12z)(given)] It is uniform field Hence its value is same every where |I|=√32+42+122=13 Nkg−1

The gravitational potential in a region is given by V = (3x + 4y + 12z) $\frac{J}{k g}$ . The modulus of the gravitational field at (x = 1, y = 0, z = 3) is

The correct option is B
$13 N k g^{- 1}$

$I = - (\frac{δ v}{δ x}^i + \frac{δ v}{δ y}^j + \frac{δ v}{δ z}^k) = - (3^i + 4^j + 12^k) [A s V = (3 x + 4 y + 12 z) (g i v e n)]$

It is uniform field Hence its value is same every where $| I | = \sqrt{3^{2} + 4^{2} + 12^{2}} = 13 N k g^{- 1}$