The greater among -17-12 and -11-6 is-

The correct option is B √(11) √(6) is the difference of smaller surds √(17) √(12) is the difference of bigger surds So, √(11) √(6) gt;√(17) √(12) nbsp; ...

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Byju's Answer

Standard IX

Mathematics

Natural Numbers

The greater a...

Question

The greater among $\sqrt{17} - \sqrt{12}$ and $\sqrt{11} - \sqrt{6}$ is:

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Solution

The correct option is B

$\sqrt{11} - \sqrt{6}$ is the difference of smaller surds

$\sqrt{17} - \sqrt{12}$ is the difference of bigger surds

So, $\sqrt{11} - \sqrt{6} > \sqrt{17} - \sqrt{12}$

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Similar questions

The greater number among $\sqrt{17} - \sqrt{12}$ and $\sqrt{11} - \sqrt{6}$ is

Among : √17- √12 and √11-√6 which is greater and how?

\sqrt{1} 7

–

\sqrt{1} 2

and

\sqrt{1} 1

–

\sqrt{6}

. Which is greater?

Q. The greater number between

\sqrt{17} - \sqrt{12}

and

\sqrt{11} - \sqrt{6}

is ____.

Q. The smallest between

\sqrt{17} - \sqrt{12}

and

\sqrt{11} - \sqrt{6}

is _________.

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The greater among √17−√12 and √11−√6 is:

The correct option is B √11−√6 is the difference of smaller surds √17−√12 is the difference of bigger surds So, √11−√6>√17−√12

The greater among $\sqrt{17} - \sqrt{12}$ and $\sqrt{11} - \sqrt{6}$ is:

The correct option is B

$\sqrt{11} - \sqrt{6}$ is the difference of smaller surds

$\sqrt{17} - \sqrt{12}$ is the difference of bigger surds

So, $\sqrt{11} - \sqrt{6} > \sqrt{17} - \sqrt{12}$