Question

The greatest amongst the the values $0.7+\sqrt{0.16},1.02-\frac{0.6}{24},1.2\times 0.83$ and $\sqrt{1.44}$ is

• A. $0.7+\sqrt{0.16}$
• B. $1.02-\frac{0.6}{24}$
• C. $1.2\times 0.83$
• D. $\sqrt{1.44}$

Answer 1

Answer: (D)

$\sqrt{1.44}$

$0.7+\sqrt{0.16}=0.7+0.4=1.1$

$1.02-\frac{0.6}{24}=1.02-0.025=1.175$

$1.2\times 0.83=0.996$

$\sqrt{1.44}=1.2$

$\therefore$ the greatest is $\sqrt{1.44}$.