The correct option is B 23!5!(6!)3
From passage, greatest coefficient in the expansion of
(x1+x2+x3......+xk)n is n!(q!)k−r((q+1)!)r
Where q and r are the quotient and remainder when n is divided by k
Now, here, n=23,k=4
⇒n=23=5×4+3⇒q=5,r=3
Hence greatest coefficient in (a+b+c+d)23 is, =23!(5!)(6!)3