The greatest height to which a man can throw a stone is h.The greatest distance to which he can throw will be
A
h/2
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B
h
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C
2 h
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D
4 h
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Solution
The correct option is C 2 h Greatest height can be achieved only if he throws the stone in vertically upward direction give by h=u2/2g so u2=2gh ...... (1)
Range or horizontal distance is given as R=u2Sin2θ/g which can be maximize if Sin2θ=1 so maximum range becomes R=u2/g
by putting the value of h from equation-1 we get R=2h