Question

The greatest height to which a man can throw a stone is h. The greatest distance to which he can throw it, will be?

• A. $h/2$
• B. h
• C. $2h$
• D. $3h$

Answer 1

The correct option is C $2h$

The maximum vertical height that the stone achieves =h

Thus the velocity with which the object s thrown upwards v$=\sqrt{2gh}$.

We know range of projectile R$=\frac{v^{2}sin2\theta }{g}=\frac{v^2}{g}$

Maximum distance can be covered when $\theta$=45 and sin2$\theta$=1

Therefore R$=\frac{2gh}{h}=\text{2h}$