The greatest integer that divides 358, 376, 334 leaving the same remainder in each case is
A
6
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B
7
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C
8
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D
9
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Solution
The correct option is A 6 The difference between each set of two numbers is respectively 18, 42 and 24. Now, as the remainder should be the same in each case, the number is the greatest common divisor of 18, 24 and 42. 18=2×3×3 24=2×2×2×3 42=2×3×7 ∴HCF=2×3=6 ∴ The required number is 6.