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Question

The greatest number that will divide 137,182 and 422 leaving a remainder of 2 in each case is

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Solution

In order to make 137, 182 and 422 completely divisible by the greatest number, we need to subtract 2 from each term, so

137-2 = 135, 182-2 = 180 and 422-2 = 420

Now HCF of 135, 180 and 420 is

135 = 3×3×3×5

180 = 2×2×3×3×5

420 = 2×2×3×5×7

Hence HCF of 135, 180 and 420 is 3×5 = 15

Hence the greatest number that will divide 137, 182 and 422 leaving the remainder 2 in each case is 15.
So the correct answer is 15.

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