The greatest number which divides $261, 933 a n d 1381$ leaving remainders $5$ in each case is

128

No worries! We‘ve got your back. Try BYJU‘S free classes today!

64

No worries! We‘ve got your back. Try BYJU‘S free classes today!

32

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

16

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C $32$
When each of the numbers $261, 933 a n d 1381$
is divided by the required number the remainder
is 5
Therefore the required number
= HCF of $(261 - 5, 933 - 5, 1381 - 5)$
= HCF of $256, 928, 1376$
= $32$

Suggest Corrections

Similar questions

77, 147

252

7

.Find the greatest number which divides 1475 and 485 ,leaving remainder 5 in each case.

137, 182 a n d 422

2

245

1029

5

Join BYJU'S Learning Program