The correct option is A π4
|z−4|=Re(z)
⇒√(x−4)2+y2=x
or x2−8x+16+y2=x2
or y2=8(x−2)
The given relation represents the part of the parabola with focus (4,0) lying above the x−axis and the imaginary axis as the directrix. The two tangents from directrix are at right angle. Hence, greatest positive argument of z is π4.