Question

The greatest possible number of points of intersection of $8$ straight lines and $4$ circles is

• A. $32$
• B. $64$
• C. $76$
• D. $104$

Answer 1

The correct option is D $104$

No. of points of intersection of line to line $={}^8{C}_2=28$

No. of points of intersection of line to circle $=2\times {}^4{C}_1{}^8{C}_1=64$

No. of points of intersection of circle to circle $=2\times {}^4{C}_2=12$

Total number of points $=28+64+12=104$