Question

The greatest range of a particle, projected up with a given velocity on an inclined plane, is $x$ times the greatest vertical altitude above the inclined plane in that condition. Find the value of $x$.

• A. $2$
• B. $4$
• C. $3$
• D. $\frac{1}{2}$

Answer 1

The correct option is A $2$

Maximum range of particle projected on on incline is given by $=\frac{u^2}{g}$

Greatest vertical altitude above the inclined plane is $=\frac{u^2}{2g}$

Maximum range of particle projected on on incline $=x\times$Greatest vertical altitude above the inclined plane

$\frac{u^2}{g}=x\times \frac{u^2}{2g}$

$⟹x=2$