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B
2
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C
3
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D
4
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Solution
The correct option is C 1 f(x)=sin3x+cos3x f′(x)=3sinxcosx(sinx−cosx) For maxima or minma, f′(x)=0 ⇒sinx=0;cosx=0;sinx−cosx=0 ⇒x=0,π2,π4 f′′(π4)>0 So, f(x) has a minimum at x=π4 f(0)=1 and f(π2)=1 So, the maximum value of f(x) is 1.