The ground state electron configuration of Fe is:

1s² 2s² 2p⁶ 3s² 3p⁶ 4s²

No worries! We‘ve got your back. Try BYJU‘S free classes today!

1s² 2s² 2p⁶ 3s² 3p⁶ 3d⁸

No worries! We‘ve got your back. Try BYJU‘S free classes today!

1s² 2s²3s² 3p⁶3d¹⁰

No worries! We‘ve got your back. Try BYJU‘S free classes today!

1s² 2s² 2p⁶ 3s² 3p⁶ 4s²3d⁶

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D
1s² 2s² 2p⁶ 3s² 3p⁶ 4s²3d⁶

This is as per the various rules for filling of electrons in various orbitals i.e. Hund's rule of maximum multiplicity, Aufbau principle and Pauli exclusion principle.

Suggest Corrections

Similar questions

The electronic configuration of Ti is 1 $s^{2}$ 2 $s^{2}$ 2 $p^{6}$ 3 $s^{2}$ 3 $p^{6}$ 3 $d^{2}$ 4 $s^{2}$ and it represents

{1 s}^{2} {2 s}^{2} {2 p}^{6} {3 s}^{2} {3 p}^{6} {3 d}^{6} {4 s}^{1}

{1 s}^{2} {2 s}^{2} {2 p}^{6} {3 s}^{2} {3 p}^{6} {4 s}^{2}

{1 s}^{2} {2 s}^{2} {2 p}^{6} {3 s}^{2} {3 p}^{1}

{1 s}^{2} {2 s}^{2} {2 p}^{6} {3 s}^{2} {3 p}^{5}

{1 s}^{2} {2 s}^{2} {2 p}^{6} {3 s}^{2} {3 p}^{6} {4 s}^{1}

{(I E)}_{1}

{(I E)}_{4}

1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{6} 3 d^{5} 4 s^{1}

Join BYJU'S Learning Program